C 12 H 22 O 11 C_{12}H_{22}O_{11}

Chemistry Level 2

What is the percentage of carbon in Table sugar(Sucrose)?

Give your answer to two decimal places.


The answer is 42.10.

Nazmus Sakib by Nazmus sakib , 24, Bangladesh

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1 solution

Nazmus Sakib
Oct 27, 2017

Sugar= C 12 H 22 O 11 C_{12}H_{22}O_{11}

Molecular mass of sugar

= 12 × 12 + 1 × 22 + 16 × 11 =12\times\ 12+1\times\ 22+16\times\ 11

= 342 =342

so the percentage of carbon in sugar

= 144 342 × 100 =\dfrac{144}{342}\times 100

= 42.1052631579 =42.1052631579

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