Calculas is interesting

Velocities of two particles are defined as v=(t+1)(t+1)(t+1) and v= 3t(t+2). At what time the both of them will attain the same acceleration?


The answer is 1.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Caleb Townsend
Feb 17, 2015

To find the time when the accelerations are equal, set them equal to one another. d d t ( t + 1 ) 3 = d d t 3 t ( t + 2 ) \frac{d}{dt} (t+1)^3 = \frac{d}{dt} 3t(t+2) Evaluate to get t 2 = 1 t^2 = 1 If time starts at 0 0 and goes positive, then the only valid solution is t = 1 \boxed{t = 1}

nice solution!

Dinamani Borah - 6 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...