Calculate the pH of a 5.6 L solution made by dissolving 0.46 mol of in water.
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N a H reacts with water as follows:
N a H + H 2 O → N a O H + H 2
So, one mole of N a H produces 1 mole of N a O H .
Since, N a O H ionizes completely, we have, [ O H − ] = [ N a O H ] ≡ [ N a H ] = 5 . 6 0 . 4 6
∴ p O H = − lo g [ O H − ] = − lo g 5 . 6 0 . 4 6
⇒ p H = 1 4 − p O H = 1 4 + lo g 5 . 6 0 . 4 6 ≈ 1 2 . 9 1