Calculate the time taken to go around the circular hoop.

Classical Mechanics Level 2

The ball is set rolling from A it reaches G after passing point C.Assume that g = 10m/s*s and that all surfaces are frictionless. Calculate the time taken for the ball to go only around the circular loop( calculate in seconds ).


The answer is 0.314.

Srinivasa Gopal by Srinivasa Gopal , 53, India

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1 solution

Srinivasa Gopal
Dec 6, 2017

Let us apply the law of conservation of energy to the ball which starts rolling at point A and first reaches point C. 

                                                                    m*g*h = 0.5*m*v*v 

                                                                    v =  sqrt(2*g*Height of AB) 

                                                                    v = sqrt(100)

                                                                  Velocity at C =  10m/s

                                        Since there is no loss of friction along CD Velocity at G = Velocity at C.

                                         Time taken to cover a distance of 2*pi*r at constant velocity = 2*pi*r/V 

                                                            Substituting  r = 0.5 = pi/10 = 0.314 seconds.
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Don't you have to add the time taken from point C to G?

John Crocker - 3 years, 6 months ago

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No have made it clear , required to calculate the time to only go around the circular loop.

Srinivasa Gopal - 3 years, 6 months ago

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Ahh my bad. There i go making the problem more complicated than it needs to be. Thanks!

John Crocker - 3 years, 6 months ago

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