Calculating the amount of chemical substance

Chemistry Level 2

Under STP conditions, the total volume of mix gases which are $10\text{ g}$ of carbon dioxide and nitrogen gas is $6.72\text{ L}$ .

What is the volume for carbon dioxide only?

6.72 \text{ L}

4.48 \text{ L}

8.6 \text{ L}

2.24\text{ L}

1 solution

Nicole Ling
Jul 20, 2016

n（CO2）+n（N2）= $\frac{6.72 L}{22.4L/mol}$ =0.3mol，

n（CO2）×44g/mol+n（N2）×28g/mol

so , n（CO2）=0.1 mol，n（N2）=0.2 mol

V（CO2）=0.1mol×22.4L/mol =2.24L

Could you please elaborate the steps ? I didn't got you?

Anurag Pandey - 4 years, 9 months ago