The current in the wire is 8A, the number of electrons passing through a certain cross section of the wire within 40s is ? (the amount of electron charge is e=1.6×10^-19 C).
Hint :The amount of charge passing through the conductor can be calculated by physics formula : Q=It
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Knowing that I = d t d q = t N q , solving for N gives:
N = q I t = 1 . 6 × 1 0 − 1 9 ( 8 ) ( 4 0 ) = 2 × 1 0 2 1 e l e c t r o n s .