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I didn't see that "x" was in fact exponent of 2. I took it as (2^2)^x. hence my answer came 4.
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Yeah I read it as 2^2x ... Looking at it again it is 2^2^x
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This happened with me too. Next time i'll read questions more carefully
the same thing happened to me...
Same can mistake
Sry common
1 6 2 2 1 6 = 2 8 2 1 6 = 2 8 2 8 = 2 2 x ⇒ x = 3
As easy as calculating powers of 2. 2 1 6 = 6 5 5 3 6 = 1 0 0 0 0 1 6 and 1 6 2 = 1 0 0 1 6 so the quotient becomes 1 0 0 1 6 = 2 8 so x = 3
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On the left hand side of the equation, we rewrite the denominator as a power of 2. The denominator is 1 6 2 = ( 2 4 ) 2 = 2 8 , so the fraction ( 1 6 ) 2 2 1 6 cancels out to 2 8 .
We take the logarithm with base 2 on both sides of the equation 2 8 = 2 2 x , giving 2 x = 8 .
Taking the logarithm with base 2 again, we end up with x = 3 .
Note: exponent towers are evaluated from the top, down. Please see this page: https://brilliant.org/wiki/what-is-a-to-the-b-to-the-c/