Calculators won't help!

Algebra Level 1

Find the value of 2014201 4 2 ( 20142004 ) ( 20142024 ) 20142014^2-(20142004)(20142024) .


The answer is 100.

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4 solutions

Linus Setiabrata
Aug 26, 2014

To make computations easier, we let a = 20142014 a=20142014 .

Then, we have to find the value of a 2 ( a + 10 ) ( a 10 ) a^2-(a+10)(a-10) .

Simplifying, we get

a 2 ( a 2 1 0 2 ) a^2-(a^2-10^2)

= a 2 a 2 + 1 0 2 =a^2-a^2+10^2

= 100 =100

And we get our final answer of 100 \boxed{100}

Then how do you explain THIS ?

John M. - 6 years, 9 months ago

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You typed an extra "0" in "200142024"

http://www.wolframalpha.com/input/?i=%2820142014%29%5E2-%2820142004*20142024%29

Linus Setiabrata - 6 years, 9 months ago

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That's what he is trying to show you. You have typed Linus. You have typed an extra 0 in your problem. Kindly edit it.

Ronak Agarwal - 6 years, 9 months ago

And what do you think am I referring to by "typo"? Check your problem.

John M. - 6 years, 9 months ago

You've made a typo in your problem. Fix it.

John M. - 6 years, 9 months ago

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This problem has been updated.

Those who previously entered -3625560719999900 have been marked correct.

Calvin Lin Staff - 6 years, 9 months ago

typo on 201420024

Reinaldo Limantara - 6 years, 9 months ago
Eric LeClair
Dec 1, 2014

You can simply take 14^2-4x24

2014201 4 2 ( 20142004 ) ( 20142024 ) = 2014201 4 2 ( 20142014 10 ) ( 20142014 + 10 ) 20142014^2-(20142004)(20142024)=20142014^2-(20142014-10)(20142014+10) 2014201 4 2 ( 2014201 4 2 1 0 2 ) 20142014^2-(20142014^2-10^2) 2014201 4 2 2014201 4 2 + 100 = 100 20142014^2-20142014^2+100=\boxed{100}

Mardokay Mosazghi
Aug 28, 2014

Not a good solution as @Linus Setiabrata but 1 4 2 14^2 - ( 24 4 ) = 100 (24*4)=100

This is the same solution I had!

Eric LeClair - 6 years, 6 months ago

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