Find the largest 32-digit perfect square.
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Largest 4 digit square = 9 9 2 = 9 8 0 1 . There is one 9 and one 0 surrounding 8 and 1 in the end.
Largest 6 digit square = 9 9 9 2 = 9 9 8 0 0 1 . There are two 9 and two 0 surrounding 8 ad 1 in the end.
Largest 8 digit square = 9 9 9 9 2 = 9 9 9 8 0 0 0 1 . There are three 9 and three 0 surrounding 8 and 1 in the end.
So, largest 32 digit square = 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 2 . It will have fifteen 9 and fifteen 0 surrounding 8 and 1 in the end.
= 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 8 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1