Let be a continuous function satisfying . Find the value of .
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If we differentiate the above equation with respect to x , then we arrive at the ODE f ′ ( x ) = f ( x ) with the initial condition f ( 0 ) = 0 . Solving this ODE produces f ( x ) = C e x and solving for the real constant C gives:
0 = C ⋅ e 0 = C ( 1 ) ⇒ C = 0
hence, f ( x ) = 0 for all x ∈ R and f ( l n ( 5 ) ) = 0 .