calculus problem

Calculus Level 2

f(x)=1+x(sinx)[cosx] 0<x<=90

where 0,x,90 are in degress. []denotes greatest integer function

has global maximum of 2 is strictly decreasing in (0,90) is strictly increasing in(0,90) is continuous in (0,90)

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2 solutions

X does belongs to interval (0,90]. If we substitute for the value of X in function,
[cosx] is always equal to zero so product sinx.[cosx] will always be zero
So function becomes constant function.

f ( x ) f\left( x \right) =1 constant function

Moderator note:

Can you explain why?

Can you explain why?

Calvin Lin Staff - 5 years, 4 months ago

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