Calculus problem #2517

Calculus Level 1

Given f ( x ) = x x + 1 f(x) = \frac{x}{x+1} , what is f ′ ( 1 ) f'(1) ?


The answer is 0.25.

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Arron Kau by Arron Kau

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4 solutions

Avirook Roy
Jan 19, 2014

usind derivative formula g(x)d/dxf(x)-f(x)d/dxg(x)/g(x)sq putting the values get the ans.

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Arun Silveru
Dec 26, 2013

d/dx(x/x+1)=d/dx[x*(x+1)^-1] by applying u.v rule we get =[-x/(1+x)^2] + 1/1+x then f'(1)=(-1/4) + 1/2 =1/4 =0.25

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Budi Utomo
Dec 26, 2013

Solution is f '(x) = 1/(x+1)^2 ---> f '(1) = 1/(2^2) = 1/4. ANSWER : 0.25.

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Nida Fatima
Dec 15, 2013

solution : darivative w.r.t x f'(x)=(x+1)-x/(x+1)^2 f'(x)=x+1-x/(x+1)^2 f'(x)=1/(x+1)^2 put x=1 f'(1)=1/(2)^2 f'(1)=0.250

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