Calorie Burner

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Given

p x + q y + r z = 1 px+qy+rz=1

p + q x + r y = z p+qx+ry=z

p z + q + r x = y pz+q+rx=y

p y + q z + r = x py+qz+r=x

p + q + r = − 3 p+q+r=-3

Find x + y + z + 1. x+y+z+1.


The answer is 0.

Nit Jon by Nit Jon , 21, USA

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1 solution

Budi Utomo
Dec 26, 2013

We know if ( x+ y + z + 1) (p + q + r ) = py + qz + r + pz + q + rx + p + qx + ry + px + qy + rz --> ( x+ y + z + 1) (p + q + r ) = (py + qz + r) + (pz + q + rx) + (p + qx + ry) + (px + qy + rz) ---> ( x+ y + z + 1) (p + q + r ) = x + y + z + 1 --->Because if both of sides divided by x + y + z + 1 for p + q + r is contradiction -3 = 1. So, x + y + z + 1 that can is 0. ANSWERED

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SINCE P+Q+R=-3

LET P= -1 Q= -1 R= -1

PUTTING VALUES IN DIFFERENT EQUATIONS

WE GET

Z=2

X+Y= -3

X+Y+Z+1= -3+(2)+(1)

0

Ashutosh Krishna - 7 years, 5 months ago

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