Calvin the Cat man

Let the ages of the cats (in ascending order) x, y, 16. Since y is the median of the ages, and 8 is the median as given, therefore, y=8. The only age left to be solved is for the youngest (x). It is said that the mean(average) of the ages is 10. So, (x+8+16)/3=10-->x+24=30-->x=6. :))

Since the age of the oldest cat is 16 and the median is of the ages is 8, we can figure out the age of the last cat by using the mean:

$\frac{x+8+16}{3} = 10$

$x+24 = 30$

$x = 6$

The age of the cat is 6.

Let the ages be x , y, z given, largest age= 16yrs. median age = 8yrs. therefore if avg. = 10, then sum of ages = 3 x 10 = 30. hence the age of smallest cat = 30-16-8=6

If the median is 8 then the ages of the cats must be 16, 8, and x. Since the mean is 10, the sum of the ages must be 30.

16+8+x=30

x=6

Total age , T = 30

T - 16 - 8 = 6

calvin having 3 cats oldest cat ---> x=16years old , middle-->y, youngest -->z mean=(x+y+z)/3=10 ----> y+z=14 median=8 ---> then assume that the middle cat age would be y=8 , i.e x=6 the youngest cat age is 6

Mean age = 10, so, the total age of the three cats is 30 .

30 - 16 = 14 ( the total age of the two remaining cats )

14 - 8(median age of one cat) = 6 * youngest cat

Let's say we have cats H, I, and J, where H is the age of Heathcliff.

Thus, H = 16.

Since the mean age of the cats is 10, (H + I + J) / 3 = 10.

The median of the cats' ages is the middle value, or the sum of the two middle values in the case of an even number of items. Since we have three cats, we know that one of the cats is 8 years old. Lets arbitrarily assign this value to I.

I = 8.

Because we now know the value of I and that H > I, we know that H > I > J. Therefore, J is the age of the youngest cat.

We can plug in our values to our mean equation to solve for J:

(16 + 8 + J) / 3 = 10

(24 + J) / 3 = 10

24 + J = 30

J = 6

The age of the youngest cat is 6.

The oldest cat is 16 (given).

Since there are only three cats, the median age is the age of the middle cat, 8 (given).

Let a be the age of the youngest cat.

Then (a + 8 + 16)/3 = 10 (Mean)

a + 24 = 30

a = 6.

Therefore, the youngest cat is 6 years old.

Well you know the oldest cat is 16 and the median means middle number so the middle aged cat is 8. Now to find the youngest cat you use the mean. 3 cats so 10 multiplied by 3=30 which is the total age of them added together. 16+8=24 so the youngest cat must be 6!

Let y denote the age of the youngest cat. Thus, from the problem we get (16 + 8 + y)/3 = 10. Solving this yields y = 6

oldest > median > youngest

mean = \frac{oldest + median + youngest }{3}

10= \frac{16+ 8+ youngest }{3}

youngest =6

{16 + x + y} / 3 = 10 x + y = 30 - 16 =14 as median is 8 then x is 14 - 8 = 6

Since the mean age is 10, the total age is 10*3=30. Since the median age is 8, the three ages (in ascending order) are x,8,16. x=30-8-16=6.