Calvin's Calorie Intake

From the conditions, we are looking for the largest number under 1000 that is a multiple of $6 \times 7 = 42$ . Since $1000/42 \approx 23.8$ , the maximum number of calories that Calvin could have consumed is $23 \times 42 = 966$ .

If Calvin eats through $7$ bags of gummy worms and each bag contains $6$ servings of gummy worms, then Calvin has eaten $7\times6=42$ servings of gummy worms. Given that Calvin has consumed just under $1000$ calories and the previous information, the number of calories Calvin has consumed must be a multiple of $42$ . Now, $1000$ when divided by $42$ gives a remainder of $34$ (in formal terms, $1000\mod42=34$ ). Thus, the closest multiple of $42$ to $1000$ must be $1000-34=966$ , the required answer.

That was so easy!

1000 // (7x6) * (7x6) = 966

Why don't you just guess and check? Just guess 6 x 23. That is 138. Then do 138 x 7. This gives you 966. I am eleven and I figured that out easily.

This question is quite interesting. 7 bags of gummy worms with 6 servings equals 42 servings of gummy worms. Each serving's number of calories is a positive integer. So you can do 1000/42, which equals 23.6, so you have to round down to get the maximum amount of gummy worms, so 23 calories each. Then you multiply 23*42 which equals 966. So that's how you get that answer.