‘Can be solved by most 13-year-olds in China‘-1

Algebra Level 3

Whole set
Given equation ( m 5 ) x + m 3 = 0 , (m-5)x+m-3=0, Where m m and x x are integers, find all possible values of m m .

Submit your answer as the product of all possible values of m m .
e.g. If m = 1 m=1 or m = 2 m=2 , submit 1 × 2 = 2 1\times 2=2 .


The answer is 504.

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1 solution

Jeff Giff
Mar 12, 2021

Re-write the equation: x = 3 m m 5 = m + 5 2 m 5 = 5 m m 5 2 m 5 = 1 2 m 5 . x=\frac{3-m}{m-5}=\frac{-m+5-2}{m-5}=\frac{5-m}{m-5}-\frac{2}{m-5}=-1-\frac{2}{m-5}.
I skipped a little on the first step :) \color{#D61F06}\small \text{I skipped a little on the first step :)}
In order for x x to be an integer, 1 2 m 5 -1-\dfrac{2}{m-5} must be equal to an integer, further implying that m 5 m-5 is a factor of 2 2 .
Note that we don’t ask for sign here, so m 5 m-5 can be equal to 1 , 2 , 1 1,2,-1 or 2 -2 .


Solving that, we get m = 6 , 7 , 4 m=6,7,4 or 3 3 . So the answer is 6 × 7 × 4 × 3 = 504 6\times 7\times 4\times 3=\boxed{504} .

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