Can Euler still help?

Algebra Level 4

If the expression i π + e + 1 i\pi + e + 1 can be expressed in the form ln ( k ) \ln(k) where k k is a real number, determine k k to three decimal places.


The answer is -41.194.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

ln ( k ) = π i + e + 1 k = e π i + e + 1 k = e π i e e + 1 \ln(k)=\pi i+e+1 \\ k=e^{\pi i+e+1} \\ k=e^{\pi i}e^{e+1}

By Euler's formula, e i x = cos x + i sin x e^{ix}=\cos x+i\sin x , so e π i = cos π + i sin π = 1 e^{\pi i}=\cos \pi + i \sin \pi=-1 , and our expression becomes:

k = e e + 1 k 41.194 k=-e^{e+1} \\ k \approx \boxed{-41.194}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...