A bird is sitting on train which is coming from left moving towards east with a velocity 300 km/hr. Another train of same speed coming from right moving in west direction on the same track. When the trains 6 km apart , the bird starts flying with a velocity 30 km/hr with respect to ground towards 2nd train (moving towards west direction). After touching the 2nd train . it turns back to 1st train (moving towards east direction) and continue repeating this process until the trains collide. In this process , the total distance covered by the bird is ... (answer in metre)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The time for the bird to fly is t = s 1 + s 2 d
= 3 0 0 + 3 0 0 6
= 1 0 0 1 hours
So the bird can fly for only 1 0 0 1 hours, what a short amount of time
1 0 0 1 ⋅ 3 0 = 0 . 3 km
= 3 0 0 m