Can it find a place here?
A sequence of natural numbers is in Arithmetic Progression whose common difference is prime relative to a natural number n . What can be said about the following statement?
There exists at least one number among n consecutive numbers of the sequence which is a multiple of n
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1 solution
I suspect there is an error in the question. The sequence 1,3,5,7,9,11 etc includes no multiples of 4 ever, as a counterexample. n needs to be co-prime with the common difference. That will work.