k = 1 ∑ 2 cos 8 ( 5 k π ) , k = 1 ∑ 3 cos 8 ( 7 k π ) , k = 1 ∑ 4 cos 8 ( 9 k π ) , k = 1 ∑ 5 cos 8 ( 1 1 k π ) , k = 1 ∑ 6 cos 8 ( 1 3 k π ) , …
Above shows a sequence of numbers, what type of sequence of progression do they follow?
Bonus : Find its common difference and/or common ratio.
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Well actually to be quite honest, I am pretty much confused myself. However, I will share my way of solving this problem. We can express cos^8(x) as, a1+a2cos(2x)+a3cos(4x)+a4cos(6x)+ a5cos(8x). The values of a(i)'s don't matter because they are constants anyways. Now, let S(n) denote the sum of cos^8(2r*pi/n), where r denotes the integers between 1 and (n-1)/2, and n is an odd integer. Therefore, S(n) equals the sum of multiple angles of 2pi/n, all of which sums up to be constant and independent of n.( If you are confused about the last statement, you may google up "n-th roots of unity".) This means that S(n) is a constant. Hence we can say it is an AP with common difference of 0. But it also can be a GP with common ratio of 1. I may be wrong in my last statement, but S(n) is definitely constant series.