Can we think out of the box?

Geometry Level 3

The reason why we cannot have a platonic solid with six equal sides (regular hexagon) on each of its surface is because:

  • A) A regular hexagon has internal angles of 12 0 120^\circ , but 3 × 12 0 = 36 0 3\times120^\circ=360^\circ (angle of the point at which three sides, one from each surface will meet) which won't work because at 36 0 360^\circ the shape flattens out.

  • B) It is possible, as it does not depend upon the internal angles rather depends upon the angles made by one surface to other.

  • C) It is possible, as while forming a polyhedron it neither depends upon the internal angle nor on the mutual angles between the surface.

  • D) None of the above.

Assumption: A Regular dodecahedron as shown above, has 5 equal sides (regular pentagon) on each of its surface, like wise the question asks the reason behind the impossibility of a polyhedron with six equal side on each of its surface.

B D A C

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1 solution

Michael Mendrin
May 6, 2016

A critical detail for A) to be the answer is that a Platonic solid is defined to be convex. Proving that intersecting regular hexagons cannot be used to form a regular non-convex solid takes a little extra work.

I totally agree with you on this. :)

Abhay Tiwari - 5 years, 1 month ago

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