Can You Break Into My House?

$•$ Lets directly move to the third hint, we get that $5 , 7, 3 , 8$ are wrong.

$•$ Now in second hint, since now $7$ is wrong we can infer that either $( 0 , 6 ) , (0,9)$ or $(6,9)$ satisfy condition of second hint.

$•$ Now, in the fourth hint, we have $8$ wrong and now observe, if $6$ was correct one then it should also be in correct position, but we have different positions for $6$ in second and fourth hints. Hence, we can infer that $6$ is also wrong. So, $0,9$ are correct and in correct positions.

$•$ So, now we have $2,9$ as correct and in correct positions.

$•$ Now, in first hint we have $5$ wrong and $2$ is correct. Hence, either of $4$ or $1$ are correct. Now the condition of first hint tells us that only one of the correct ones are in correct position. From above, we have that $2$ is in correct position.

$•$ Now, from above $2$ is in first position, $0$ is in second position and $9$ is in fourth position. If $4$ was correct then it infers that as only third position is left and $4$ is in third position. Hence, it does not satisfy the condition of first hint. Hence, $1$ is correct.

Hence, Code is $\boxed{2019}$

If you broke the code, you are invited to