Can you calculate

Geometry Level 3

Calculate without using trigonometric tables

4 c o s 2 0 3 c o t 2 0 4cos20^{\circ}- \sqrt{3}cot20^{\circ}


The answer is -1.

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1 solution

Rishi Hazra
Nov 5, 2014

=> 2 * { ( 2 * cos 20 * sin 20 ) - ( sin 60 * cos 20 )} / sin 20

=> 2 * { ( sin 40 - sin 60 * cos 20 ) / sin 20

=> 2 * { ( sin 60 * cos 20 - cos 60 * sin 20 - sin 60 * cos 20 ) / sin 20 ....................................[ sin 40 = sin ( 60 - 20 ) = sin 60 * cos 20 - sin 20 * cos 60 ]

=> -1

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