Two bodies of masses M 1 and M 2 are initially at rest at infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity of approach at a separation distance r between them is __________ .
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This is a two-body problem. We can turn it into a one-body problem using the reduced mass μ . We know that δ K = − δ U from conservation of energy, so all we have to do is use find v .
− ( − G r M 1 M 2 − 0 ) = 2 1 μ v 2 G r M 1 M 2 = 2 1 ( M 1 + M 2 M 1 M 2 ) v 2
Just solve for v .