Can you feel the gravity?

Two bodies of masses M 1 { M }_{ 1 } and M 2 { M }_{ 2 } are initially at rest at infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity of approach at a separation distance r r between them is __________ \text{\_\_\_\_\_\_\_\_\_\_} .

( 2 G ( M 2 M 1 ) r ) 1 2 { (\frac { 2G({ M }_{ 2 }-{ M }_{ 1 }) }{ r } })^{ \frac { 1 }{ 2 } } None of these choices ( 2 G M 2 M 1 r ) 1 2 { (\frac { 2G\sqrt { { M }_{ 2 }{ M }_{ 1 } } }{ r } })^{ \frac { 1 }{ 2 } } ( 2 G ( M 2 + M 1 ) r ) 1 2 { (\frac { 2G({ M }_{ 2 }+{ M }_{ 1 }) }{ r } })^{ \frac { 1 }{ 2 } }

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1 solution

Andrew Yates
Feb 20, 2016

This is a two-body problem. We can turn it into a one-body problem using the reduced mass μ \mu . We know that δ K = δ U \delta K = - \delta U from conservation of energy, so all we have to do is use find v v .

( G M 1 M 2 r 0 ) = 1 2 μ v 2 G M 1 M 2 r = 1 2 ( M 1 M 2 M 1 + M 2 ) v 2 -\big( -G \frac{M_1 M_2}{r} - 0 \big) = \frac{1}{2} \mu v^2 \\ G \frac{M_1 M_2}{r} = \frac{1}{2} \Big( \frac{M_1 M_2}{M_1 + M_2} \Big) v^2

Just solve for v v .

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