Can you fill in these boxes?

The example solution for this would be: $\boxed{1}\boxed{8}\times \boxed{5}\boxed{4} = \boxed{7}\boxed{0}\boxed{9} + \boxed{2}\boxed{6}\boxed{3} = 972$ .

I'm new to this part of the community so I'll just post my code here... Python of course...

import itertools
solList = []
for combo in itertools.permutations([0,1,2,3,4,5,6,7,8,9]): #Brute force basically.
    a = (combo[0]*10+combo[1])
    b = (combo[2]*10+combo[3])
    c = (combo[4]*100+combo[5]*10+combo[6])
    d = (combo[7]*100+combo[8]*10+combo[9])
    if a*b == c+d and len(str(c+d)) == 3: #Make sure both conditions hold
        solList.append(c+d) 

solList = sorted(solList) #Get largest value by sorting and reversing the list of solutions
solList.reverse()
print solList[0]