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How many 3-digit whole numbers are divisible by 7?


The answer is 128.

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1 solution

Deeponjit Bose
Oct 13, 2015

Solve This using AP

Taking a=105 [As 105 is the smallest 3-DIGIT number divisible by 7] AND d=7 [Difference between two consecutive multiples of 7 is 7] and LAST TERM(l)= 994 [As it is the greatest 3-DIGIT number divisible by 7]

AP:- 105, 112, 119,..., 994 [All the numbers in the given AP is divisible by 7] According to the AP formula,

  a+(n-1)d=l

=>105+(n-1)7=994

=>(n-1)=889/7

=>n=128 [ANS] Thus, we know there are 128 3-DIGIT nos. exactly divisible by 7

I solved it in a different way - checked how many 3-digit numbers exist: 999-100=899. Now, one in seven numbers divides by seven, so 899/7=128(3), so answer is 128.

Gadi Keller - 5 years, 7 months ago

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This is correct but solving this kind of sums using AP is the correct method.

Deeponjit Bose - 5 years, 4 months ago

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