Can you find the area?

Thank you so much for appreciating my effort! HERE is how to crack it: since ABCD is a rectangle,the opposite sides are equal.thus AB=CD and BC=AD . Now,let's consider AB=CD=x and BC=AD=y .so the area of the rectangular is xy .
The area of EBFD=xy- $\frac{1}{2}$ . $\frac{x}{2}$ .y- $\frac{1}{2}$ . $\frac{y}{2}$ .x
or, 9=xy-( $\frac{xy}{4}$ + $\frac{xy}{4}$ )
or, 9=xy- $\frac{xy}{2}$
or, 9= $\frac{xy}{2}$
or, xy=9*2=18.and xy is the area of the rectangle.

Since F is the midpoint of CD, triangles CFB and FBD have equal bases and equal heights. So they have equal area.

Similarly, triangles DEB and AEB have the same area.

FBD and DEB add up to 9. So their partners add up to 9. Making a total of 18 for the whole rectangle.