Can you find the number!

Let $\square$ denote an operation between $a$ and $b$ , which are two integers. Then, by the pattern, we can see: $\begin{aligned} \red{1} \square \blue{1} &= \overline{\red{1^2}(\red{1} + \blue{1})\blue{1^2}} \\ \red{1} \square \blue{2} &= \overline{\red{1^2}(\red{1} + \blue{2})\blue{2^2}} \\ & \ldots \\ \red{a} \square \blue{b} &= \overline{\red{a^2}(\red{a} + \blue{b})\blue{b^2}} \end{aligned}$

Thus: $\begin{aligned} \red{2} \square \blue{3} &= \overline{\red{2^2}(\red{2} + \blue{3})\blue{3^2}} \\ &= \boxed{459} \end{aligned}$

The digit in 100's place is the square of the first number in the equation. The digit in 10's place is equal to the sum of both the numbers. Unit digit is equal to the square of the second digit in the equation.So,

2 + 3=( $2^{2}$ )(2 + 3)( $3^{2}$ )

   =459