What is the 8th number in this series?
12, 6, 4, 3, 12, 2, 12...
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In this problem, the pattern is this: the nth term is the denominator in the simplified form of the fraction: (12-n)/12. So it goes 11/12, 5/6, 3/4, 2/3, 7/12, 1/2, etc. Therefore the 8th term is 3.