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In this question x is the sum of all the terms in the series .
The series 2 4 + 3 6 + 4 8 + 6 0 . . . . . . + 2 4 0 is in A.P with common difference d = 3 6 − 2 4 = 1 2 and the first term a = 2 4
First we have to find the number of terms n
Last term = 2 4 0 = a + ( n − 1 ) d ⇒ 2 4 0 = 2 4 + 1 2 ( n − 1 )
⇒ 1 2 ( 2 + n − 1 ) = 2 4 0 ⇒ n + 1 = 2 0
So, the number of terms in the series n = 1 9
Now we will find the sum of series using the formula 2 n × ( f i r s t − t e r m + l a s t − t e r m ) (or) 2 n × ( 2 a + ( n − 1 ) d )
⇒ 2 1 9 × ( 2 4 + 2 4 0 ) = 1 9 × 2 6 4 = 2 5 0 8
Therefore , x = 2 5 0 8