Can you find the value of $x$ ?

The answer is here.

$2^{ 4x-1 }\cdot 9^{ 4x-1 }\cdot 25^{ 6x-1 }=625^{ x }\\ \frac { { \left( 2\cdot 9\cdot 25 \right) }^{ 4x }\cdot { 25 }^{ 2x } }{ 2\cdot 9\cdot 25 } ={ 25 }^{ 2x }\\ { \left( 2\cdot 9\cdot 25 \right) }^{ 4x }=2\cdot 9\cdot 25\\ \therefore \quad 4x\quad =\quad 1\\ x\quad =\quad \frac { 1 }{ 4 } =0.25$

Simplify to $(625^x)\times(450)^{4x-1} = 625^x$ , or simply $x = \frac{1+log_{450}1}{4} = 0.25$

2^(4x - 1) 9^(4x - 1) 25^(6x - 1) = 625^x, or 18^(4x - 1)*25^(4x - 1) = 1, or 450^(4x - 1) = 1, so 4x - 1 = 0, and x = .25