v = 9 0 0 km/h (typical cruising speed) and at an altitude where the vertical component of the Earth's magnetic field is B = 5 0 μ T . The wingspan of the 777 is about 60 m. Determine the induced voltage in Volts across the tips of the wings.
A Boeing 777 is flying due north at
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B = 50 * 10^-6 T
v = 900 * 5/18 = 250 m/s
L = 60 m
emf = BLV
emf = 50 * 10^-6 * 250 * 60 = 0.75 volts
no way was confused with the pattern of answering :(
what's b?
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It is the magnetic field and measured in teslas
SAME METHOD I WAS USED...
forgot changing the velocity :(
Use the concept of Motional EMF. The induced voltage is BvL = 0.75V, when numbers are plugged in with correct SI Units.
damn....used it in mph instead of mps!!!!....
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next time you copy the same comment from someone else , try to change a little in it :D
Hi guys..can someone please help me with my 4th year high school physics?please..I'm not that smart like u guys..I need help.
The voltage V generated on moving a conductor by a magnetic field B is given by Faraday's Law or the rate of change of magnetic flux: V = Δ t Δ ( B A ) , where A is the area perpendicular to the magnetic field covered by the conductor in time t .
For a plane flying with a speed v = 9 0 0 k m / h , wingspan l = 6 0 m , in a constant magnetic field B , the voltage generated:
V = Δ t Δ ( B A ) ⇒ V = Δ t B Δ A = B v l = 5 0 × 1 0 − 6 × 6 0 × 6 0 9 0 0 × 1 0 0 0 × 6 0 = 0 . 7 5 V
Voltage/Potential difference = Work Done/ Time
Work Done = Force * Distance
Force = BQv
v = 250m/s
B= 50*10E-6
therefore, volt = 50*10E-6 * 250 * 60 = 0.75 V
E = Blv; B= 50 micro tesla; l=60m; v=900 km/hr=250 m/s; E= 0.75 V
EMF or electromagnetic force is the product of L, v and B where L is length in meters, v is the speed in m/s and B is in Tesla.
Oh, answer is NO :-)
damn....used it in mph instead of mps!!!!.....
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Oh the classic Brilliant E&M question...
First off, convert the velocity from km/h to m/s
9 0 0 h k m = 2 5 0 s m
Now, as the conducting plane flies through this uniform magnetic field, the charges inside will feel a magnetic force which will cause the positive charges to move to the left tip. This new movement of charge (which is otherwise known as current) will also feel a magnetic force that will point backwards. So that means that the plane must be exerting a force so that it can maintain a constant velocity, thereby holding the force felt by the charges due to their initial northward velocity constant. This force is simply the electric force.
F e l e c t r i c = F m a g n e t i c
E q = q ∣ v × B ∣
E = v B (the velocity and magnetic field are always perpendicular)
Voltage in an ideal circuit is equal to the constant electric field within the circuit times the distance/length of the wire.
V = E d = v B d
Plug in 2 5 0 s m for v , 5 0 μ T for B , and 6 0 m for d .
V = 0 . 7 5 V