Can you arrange the numerals 1 to 9 (1, 2, 3, 4, 5, 6, 7, 8 and 9) in a single fraction that equals exactly 1/3 (one third)? If So,what is the sum of digits in its Numerator?
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How did you arrive at that fraction?Please explain clearly!
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Trial and Error Method :p
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Is there no other way to solve it? @Dhinesh Ganesan
ooh, tricky problem, this one, being that there are 2 such fractions
do we have any other method to solve it ?
There are two possible fractions:
1 7 4 6 9 5 8 2 3 = 1 7 4 9 6 5 8 3 2 = 3 1
Both numerators have the same digits and their sum = 2 + 3 + 5 + 8 = 1 8
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THE POSSIBLE FRACTIONS ARE 5832/17496 = 1/3
5823/17469 = 1/3
5+8+3+2=18 .