Can you ?part;2
Compute n = 1 ∑ ∞ e n 1 up to 2 decimal places.
The answer is 0.58.
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2 solutions
Or the simple geometric progressions logic :P :P
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@Krishna Ar Can you explain this to me?
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Yeah sure..using converging geometric sum we get this to be equal to the form of a geometric series with a=1/e and r=1/e...then you can carry on.(using sum=a/1-r)
Nice explanation...tnx
n = 1 ∑ ∞ e n 1 = n = 1 ∑ ∞ e − n = 1 − e − 1 e − 1 = e − 1 1 ≈ 0 . 5 8 Since e − 1 < 1
the maclaurins series expansion of
=> (1-x) ^ (-1) = 1 + x + x^2 + x^3 + x^4 + -------------------------------------
=> put x= 1/e