Can you solve me ?
let n be an integer that indicates the sequence index where n ∈ {0,1,2,3,4...} Let the Sequence t be : π, , , , ,.... Find a₁₀ + a₁₁ ?
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1 solution
we see that any term that involves pi is equal to --> π * 2 n 1 where n is the sequence index on the other hand any term that involves ℇ is equal to --> ℇ * 3 n 1 where n is the sequence index we notice that when we try to find the term that involves π we see that n is always even where in the case of finding a term that involves ℇwe see that n is always odd. therefore a₁₀ is a term that involves pi and a₁₁is a term that involves ℇ since n is even a₁₀ -- > π * 2 ( 1 0 ) 1 since n is odd a₁₁-- > ℇ * 3 ( 1 1 ) 1 if we add a₁₀ + a₁₁ we get 3.083E-3