CAN YOU SOLVE THIS ???
A person is asked to put in a basket one apple when ordered 'One',one guava when ordered 'Two',one orange when ordered 'Three' and is asked to take out from the basket one apple and one guava when ordered 'Four' and 'Five' respectively.
4 4 5 4 5 3 4 5 3 1 4 5 3 1 2 4 5 4 5 3 4 5 3
If 8 of each type of fruits are already in the basket then,how many apples will be there in the basket at the end of the above order sequence?
The answer is 2.
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1 solution
As only "1" and "4" affect the number of apples, we only need to care about these numbers. This makes the numbers now: 4 4 4 4 1 4 1 4 4 4.
There are 8 "4"s and 2 "1"s, meaning 8(-1) and 2(+1)
8-8+2=2