CAN YOU SOLVE THIS ???

Each pixel can have around 16 million colors, so we need 24 bits to represent one pixel (on 24 bits we can write 2^24 = 16777216 different values), that is 3 bytes.

So, to represent 1024 1280 pixels we need 3 1024*1280 = 3932160 bytes, which is more than 3MB, but less than 4MB (or more precisely, it is 3.75MB).

Therefore the correct answer is 4MB.

Each pixel represents 3 bytes (one for each R, G, B) so 1024*1280 pixels = 1,310,720 pixels = 3,932,160 bytes = 3.75 MB

$log_{2}(16,000,000)=23.93$ so we requite 24 bits to represent 16,000,000 values. 24 bits divided by 8 gives us 3 bytes per pixel $1024\times1280 pixels \times 3 bytes$ gives 3,932,160 bytes

3,932,160 bytes divided by 1024 gives 3,840kb

3,840kb divided by 1024 gives 3.75MB so we need 4MB