CAN YOU SOLVE THIS ???

68000-1200X = 42000+800X X = 13

Let $a =$ Village X , $b =$ Village Y & $y =$ Years

The population of $a$ decreases by twelve hundred every year from sixty eight thousand, the equation for this process ends up being

$a = 68,000 - 1200y$

The population of $b$ increases by eight hundred every year from forty two thousand, the equation for this process is

$b = 42,000 + 800y$

Since we are looking for a time when both village's population is equal we can say that $a = b$ , in this case the following equation will allow us to work out $y$

$68,000 - 1200y = 42,000 + 800y$

First take $42,000$ to get

$26,000 - 1200y = 800y$

Then add $1200y$ to make

$26,000 = 2000y$

Now we divide by $2000$ to give us

$y = 13$

So it takes $13$ years for both villages population to be equal

let the n.o of years in which the population of villages become same be 'a'

=>68000-1200a=42000+800a

=>68000-42000=800a+1200a

=>26000=2000a

=>a=26000/2000

=>a=13

therefore n.o in which the population of the village same is 13 years