can you solve this?

Having a bit of trouble with Latex...

$I=\int _{ 0 }^{ 1 }{ \frac { { x }^{ 3 }-1 }{ \log { x } } dx } \\ \quad =\int _{ 0 }^{ 1 }{ \frac { { x }^{ 3 } }{ logx } dx } -\quad \int _{ 0 }^{ 1 }{ \frac { 1 }{ logx } dx } \\ \quad =\quad \quad \quad \quad { I }_{ 1 }\quad \quad \quad \quad -\quad \quad { I }_{ 2 }$

${ I }_{ 1 }=\int _{ 0 }^{ 1 }{ \frac { { x }^{ 3 } }{ logx } } dx\\ \quad =\int _{ 0 }^{ 1 }{ \frac { 4 }{ 4 } \frac { { x }^{ 3 } }{ logx } } dx\\ \quad =\int _{ 0 }^{ 1 }{ \frac { { 4x }^{ 3 } }{ { log\quad x }^{ 4 } } dx } \quad \quad \\ \quad Let\quad { x }^{ 4 }=t\\ \quad \quad \quad \quad 4{ x }^{ 3 }dx=dt\\ when\quad x\rightarrow 0,\quad t\rightarrow 0\\ \quad \quad \quad \quad \quad x\rightarrow 1,\quad t\rightarrow 1\\ So,\\ { I }_{ 1 }=\int _{ 0 }^{ 1 }{ \frac { 1 }{ logt } } dt$

$Hence,\\ I=\quad { I }_{ 1 }\quad -\quad { I }_{ 2 }\\ =\int _{ 0 }^{ 1 }{ \frac { 1 }{ logt } dt } \quad -\quad \int _{ 0 }^{ 1 }{ \frac { 1 }{ logx } } dx\\ =\quad 0\\ =\quad log1$

Please tell me where am I wrong ??