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Algebra Level pending

If h(x) = 3 x^2 - 7 x - 5

find h(x - 2).

4x^2+13x-5 6x^2+20x+6 10x^2-3x-1 3 x^ 2 - 19 x + 7

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2 solutions

Substituting h ( x 2 ) = 3 ( x 2 ) 2 7 ( x 2 ) 5 h(x-2)=3(x-2)^2-7(x-2)-5 .

Comparing the coefficient of x 2 x^2 with those in the available choices, there is only one option with 3 x 2 + 3x^2+\cdots

Substitute x by x - 2 in the formula of function h

h(x - 2) = 3 (x - 2)^ 2 - 7 (x - 2) - 5

Expand and group like terms

h(x - 2) = 3 ( x^ 2 - 4 x + 4 ) - 7 x + 14 - 5

= 3 x^ 2 - 19 x + 7

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