Can You Solve This ?

A circle is drawn whose centre is the focus of the parabola ${ y }^{ 2 }=16x$ . Both the ends of latus rectum of the parabola are points on the circle. At the end of latus rectum in the 4th quadrant, a tangent is drawn to the parabola which intersect the circle at a point B on the x-axis. A triangle is formed having its vertices as the end points of latus rectum and the point B. The area of this triangle is a root of the cubic equation ${ x }^{ 3 }-69{ x }^{ 2 }+326x-384=0$ . The other two roots of this cubic equation are 'a' and 'b'.

If $g(x)={ x }^{ 2 }-5x+4$ then $g(x)+b=0$ also have the roots a and b, then find the which of the following points lie on the curve $xy = a/b$ :