30 Sum-thing

The numbers given are all odd and the sum of three odd numbers is an odd number but 30 is even. Therefore, $\boxed{\text{it in not possible}}$ .

The numbers given here are odd numbers.. Besides the term of the sum $n=3$ is an odd term. But the result given finally is $30$ ; an even number!.. It's totally impossible.. Because, $n \in O$ ; Where $O$ is the set of odd numbers.. And The odd termth sum of odd numbers can never be an even number.. So, \color\red\boxed{Impossible}

Clearly Odd numbers are of the form 2k+1 So sum of three odd number Which can be taken as 2a+1 2b+1 2c+1 Is given as- 2(a+b+c) +3 = 2(a+b+c) +2+1 =2(m) +1 which is odd Hence it is not possible

• All odd numbers can be written in the form $2n+1$
• The set of numbers we have been giving are also all odd. 30 is even, and can be written as $2k$
• The equation can then be put into the form $\\ \\ (2a+1)+(2b+1)+(2c+1)=2k \\ 2(a+b+c)+3=2k$
• If we evaluate each term on the left seperately, we find that $2(a+b+c)$ is even and $3$ is odd, making it impossible for the sum of the right side to be even.

And yes, I do realise that this explanation is unnecessarily long.

The sum of three odd numbers is odd number, but 30 is even number.