Can you solve this??? ^_^

Geometry Level 2

Find the value of k for which the equation x^2 + y^2 + 4x -2y -k =0 represents a point circle.


The answer is -5.

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1 solution

Varun Suvarna
Oct 28, 2014

The general equation of a circle is

( x H ) 2 (x-H)^{2} + ( y K ) 2 (y-K)^{2} = R 2 R^{2}

where,

  • H > abscissa of center of circle

  • K > ordinate of center of circle

  • R > radius of circle

Now, the general equation of the circle is

x 2 x^{2} + y 2 y^{2} + 2gx + 2fy +c = 0

where,

  • g= -H

  • f= -K

  • c= H 2 H^{2} + K 2 K^{2} - R 2 R^{2}

Now, on comparing with the given equation, we get,

H= -2 and K= 1 and c= -k

Now, again, for a point circle, radius should be zero(i.e. R= 0 ).

Therefore, we can apply that

c= H 2 H^{2} + K 2 K^{2} - R 2 R^{2}

=> c= ( 2 ) 2 (-2)^{2} + ( 1 ) 2 (1)^{2} - ( 0 ) 2 (0)^{2}

=> c= 4 + 1

=> c= 5

=> k = 5 \boxed{k= -5}

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