( lo g 1 0 1 0 0 ) ( lo g 1 0 9 9 ) ( lo g 1 0 9 8 ) ( lo g 1 0 9 7 ) ⋅ ⋅ ⋅ ( lo g 1 0 ( − 1 0 0 ) ) = ?
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Yes correct. Note that a common mistake students make is to consider Zero Product Property without checking that all the terms (being multiplied) are defined and finite.
You should give the termination term. One can assume that it ended on x=1.
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Even i thought the same
when i solved this problem worth 210 points
I agree. It would clarify the problem more.
In the problem, it was given until log(-100), How can you assume
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this question is modified . Question was different when I solved.
The termination term is given -100. So for any negative number the logarithm is undefined.
I forget log10(0) is undefined I thought that log10(1)=0 and hence all the term become zero
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The logarithm of a negative number is complex but log(0) is in fact undefined. Without that term in product would be zero.
I too assumed it to end at x=1 and therefore got 0 as the answer
Even i did the same..
Undefined x 0 is undefined.
I don't think it depends on finite terms. Anything multiplied by ZERO (0) gives zero no matter what. CORRECT ME IF I M WRONG.
Log of negative numbers doesn't have sense in Real Numbers
Log of zero, and negative quantities is not defined,
Log0 isn't defined as well as logarithm of negative numbers its simply goes to complex number so real number shouldn't be answer
Log doesn't meant for negative numbers .
log base 10 to negative 100 is undefined, therefore the answer would not be a whole number, therefore none of those choices fit the criteria as a right answer.
Anything past log 1 is undefined. You cannot have a log of a negative number of of zero.
log1=0 , log 0 undefined , thereis no log negative numbers so the answer is undefined
Logarithm of zero and negative numbers are not defined, i guess, hence there cant be a definite answer it
log is not defined for any negative numbers, unless we allow complex solutions. Even then, log(0) is not defined.
only by inspection the alternative selected was found to be rational.
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( lo g 1 0 1 0 0 ) ( lo g 1 0 9 9 ) ( lo g 1 0 9 8 ) ( lo g 1 0 9 7 ) . . . . . . . . . . . . . . ( lo g 1 0 0 ) . . . . . . . .
But lo g 1 0 0 is not defined
Try this one