Can you solve this without Calculus?

Algebra Level 3

Find the minimum value of x + 25 x x + \frac{25}{x} .

Provided that x > 0 x>0 .


The answer is 10.

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5 solutions

Let's use the A.M-G.M. inequality

We know that A . M G . M A.M \geq G.M if each of the individual terms are positive .

x + 25 x 2 x 25 x x + 25 x 10 \dfrac{x + \frac{25}{x}}{2} \geq \sqrt{ x\cdot \frac{25}{x}} \\ \Rightarrow x + \frac{25}{x} \geq 10

Q.E.D

I think that it must be specified in the question that x > 0 x > 0 .

@Paul Ryan Longhas

A Former Brilliant Member - 6 years, 3 months ago

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Oh I see. Thanks for that :D

Paul Ryan Longhas - 6 years, 3 months ago

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You are welcome :)

A Former Brilliant Member - 6 years, 3 months ago

It would be better if you elaborate the steps in simplification for a better understanding! :|

James Bacon - 2 years, 8 months ago
Paul Ryan Longhas
Feb 28, 2015

x + 25 x = 1 x ( x 5 ) 2 + 10 10 x+ \frac{25}{x} = \frac{1}{x}(x-5)^2+10 \geq 10

Vaibhav Prasad
Feb 28, 2015

It should be stated 'minimum positive value', but anyways.

25 25 has the factors 1 , 5 , 25 1,5,25

which when taken as x x give 26 , 10 , 26 26, 10, 26

Hence, 10 10

Not positive , it should have been non-negative .

Edwin Gray
Jul 7, 2018

The expression is the sum of the straight line y+x and the hyperbola y = 25/x. We note that the smallest value for x is when the "curves" intersect; i.e. x= 5, Then the sum is 5 + 25/5 = 10. Ed Gray

i use the derivative formula, is it the calculus stuff that i shouldn't use?

f(x) = x + 25/x

f'(x) = (x^2 - 25)/x^2

f'(x) = 0

(x^2 - 25)/x^2 = 0

x^2 - 25 = 0

x^2 = 25

x = 5 since x > 0

put it in the function so

5 + 25/5 = 10

Yes, it is the calculus stuff you shouldn't have used!

James Bacon - 2 years, 8 months ago

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Lol this guy understood the right thing :D

Syed Hamza Khalid - 2 years, 8 months ago

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