sin 3 θ + sin 2 θ − sin 3 θ − sin 2 θ = sin 3 θ
Given that 0 ∘ < θ < 9 0 ∘ , and θ is a whole number, what is the value of sin 3 θ ?
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If you square both sides and write both sides in terms of sin(theta), you can get a polynomial equation (squaring again) which has solution 1/2, leading to the given solution. I have more work to do to see if there are other non-extraneous possibilities. If the difference of the two sides is monotonic, that would show uniqueness, something I have not had the time to try.
I worked out the equation. If there are other values of u = cos(theta), they would be roots of the polynomial 128u^9 + 64u^8 - 352u^7 - 48u^6 + 408u^5 - 84u^4 - 258u^3 + 87u^2 + 76u - 16. Someone with a factoring algorithm might be able to complete the analysis.
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But why are you making more complications to the problem ? We always find an easier way to solve problems in mathematics.
Sahil, the statement implies the equation has a unique solution. Finding one solution does not prove there are not others. My remarks dealt with this uncertainty.
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Listen what I have done satisfies the given conditions right? So its not uncertain.
See by logic we know sin 3theta is integer bcuz the question states that, now theta ≠0 So theta might be 1 or - 1, now try both of these as u have 3 answers and u get ur answer
Also theta is bw 0 and 90 so answer is 1, Understand everybody, I am the next imo gold medalist
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This problem can be solved by hit and trail. As 0 ∘ < θ < 9 0 ∘ , I took a value 3 0 ∘ then s i n 3 θ becomes s i n 9 0 ∘ which is equal to 1.