What is the next number in this sequence?
1 , 1 , 1 , 1 , 2 , 1 , 1 , 3 , 3 , 1 , 1 , 4 , 6 , 4 , 1 , 1 , 5 , 1 0 , 1 0 , 5 , 1
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nice one!!
Nice! :)
Nice
its the pascal triangle...!!
nice prblm
even when you consider the 0th row of pascal triangle, It doesn't justify the 1st "1" ! plzz clarify :)
Think of powers of 11. 1, 11, 121, 1331, 14641, 15 10 10 51, etc. The next digit 'ought to be 1, because the next power of 11 starts in 1.
but that doesn't explain the first two digits... please reply...
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The "0th" row of Pascal's Triangle is 1, the 1st row is 1 1, the 2nd is 1 2 1 and so on.
yeah..that was cool
first digit is 11^0 in second 11^1 so 1,1,1
11^5 is equal to 161051.. not 15101051 :)
I don't understand the problem
It was Pascal's triangle. Thanks for posting the question.
*this is * Right
Its Pascal's triangle .. so next series will be 1,6,15,20,15,6,1 . 1 is the no. Which we require.
0C0, 1C0,1C1, 2C0,2C1,2C2, 3C0,3C1,3C2,3C3, 4C0,4C1,4C2,4C3,4C4, 5C0
=> Next term = 1
Let's group this way, { 1 } {1-1} {1-2-1}{ 1-3-3-1 }{ 1-4-6-4-1 }{ 1-5-10-10-5-1}
No. of digits in a group : 1, 2, 3, 4, 5, 6 .. Also see the number of central element/s (or the largest element/s) : 1, 2, 1, 2, 1, 2, 1, 2, ...
The next pair should be a 7 digit number with a single central element, and ovbiously it should strat and end with 1's.
Therefore the answer is 1.
just follow ur mind word
Answer is one by Pascal's triangle
A simple sequence of pascelen triangle..........
pascal triangle..........................
I was thinking binomial expansion
11^0=1,11^1=11,11^2=121,11^3=1331,11^4=14641,11^5=161051 digits overlaps 1(5(1)0)1051
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This sequence is part of the Pascal Triangle. The sequence starts at the top of the triangle which is one and when you reach at the end of the row you go down a line and start from the left. This can also be interpreted as a binary tree where at the end of each root, two more roots grow and if two roots join together they add up to create one number.