As shown below, the diagram consists of four concentric circles and the positive-integer-valued widths . Both yellow and orange regions have the same combined areas, which exist for .
But is it possible for ?
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Andrew Hayes' solution to part 1 has z 1 > z 4 :
( z 1 , z 2 , z 3 , z 4 ) = ( 7 , 1 , 3 , 1 ) .