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It also depends on the value of 6
Let ' x ' be 2 .
And if ' x ' is 2,
6 x = 2 × 6 = \boxed{12}
6+ x = 6 + 2 = \boxed{8}
Let ' x ' be 0.5 .
And If ' x ' is 0.5,
6 x = 6 x 0.5 = \boxed{3}
6+ x = 6+0.5 = \boxed{6.5}
So, the answer is dependant on ' x '. ' x ' in this context has a mystery value. Therefore, it is dependant on ' x ' as shown above.
6 × 1 = 6 while 1 + 6 = 7 or 6 × 2 = 1 2 while 2 + 6 = 8 . Therefore, it depends on the value of x .
suppose, x=1
so, 6x=6 and (x+1)=7.................................[here (x+1)>6x]
again ,if x=10. then, 6x=60 and (x+1)=11.................[here 6x>(x+1)]
so, it depends on the value of x
Set up an inequality such that x + 6 < 6 x Then solve: 6 < 5 x 1 . 2 < x . Therefore, the above inequality holds true only when x > 1 . 2 . When x = 1 . 2 , x + 6 = 6 x , and when x < 1 . 2 , x + 6 > 6 x
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When 6 x = x + 6 ⟹ 5 x = 6 ⟹ x = 1 . 2 . When x > 1 . 2 , 6 x > x + 6 . When x < 1 . 2 , 6 x < x + 6 .
Therefore, it depends on the value of x .