Let a , b , c and d be real numbers satisfying a 4 + b 4 + c 4 + d 4 = 1 6 . Find the maximum value of a 5 + b 5 + c 5 + d 5 .
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A more intuitive approach is to use the substitution w = a 4 etc, and see that we want to maximize ∑ w 4 5 given ∑ w = 1 6 . We can then apply the theory of convex functions to see that the maximum is achieved at the end points.
explain me more clearly, karthik
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Note : This is just a simple version of this problem .
Solution :
a 4 ≤ a 4 + b 4 + c 4 + d 4 = 1 6 ⇒ a ≤ 2 ⇒ a 5 ≤ 2 a 4 . Similarly, it can be proved that b 5 ≤ 2 b 4 , c 5 ≤ 2 c 4 and d 5 ≤ 2 d 4 . Adding these up, we get a 5 + b 5 + c 5 + d 5 ≤ 2 ( a 4 + b 4 + c 4 + d 4 ) = 3 2 , and equality holds if and only if one of a , b , c , d is 2 and rest all are zero.
[This problem is taken from the book "Inequalities" by Zdravako Cvetovski. It is a nice book, and I recommend it for beginners]